(x^2-4x+5)(2x+5)=

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Solution for (x^2-4x+5)(2x+5)= equation: 


Simplifying
(x2 + -4x + 5)(2x + 5) = 0

Reorder the terms:
(5 + -4x + x2)(2x + 5) = 0

Reorder the terms:
(5 + -4x + x2)(5 + 2x) = 0

Multiply (5 + -4x + x2) * (5 + 2x)
(5(5 + 2x) + -4x * (5 + 2x) + x2(5 + 2x)) = 0
((5 * 5 + 2x * 5) + -4x * (5 + 2x) + x2(5 + 2x)) = 0
((25 + 10x) + -4x * (5 + 2x) + x2(5 + 2x)) = 0
(25 + 10x + (5 * -4x + 2x * -4x) + x2(5 + 2x)) = 0
(25 + 10x + (-20x + -8x2) + x2(5 + 2x)) = 0
(25 + 10x + -20x + -8x2 + (5 * x2 + 2x * x2)) = 0
(25 + 10x + -20x + -8x2 + (5x2 + 2x3)) = 0

Combine like terms: 10x + -20x = -10x
(25 + -10x + -8x2 + 5x2 + 2x3) = 0

Combine like terms: -8x2 + 5x2 = -3x2
(25 + -10x + -3x2 + 2x3) = 0

Solving
25 + -10x + -3x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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